Hey all, I can't seem to find the math on a thread to do this. Hoping to get y'alls help.
Here is the scenario.
1. Two JKR led JML squads.
2. They are both getting the same pre encounter speed buff as there is no difference in Jedi/OR counts between the two teams.
3. Team One Speeds: JML - 539, JKR - 324
4. Team Two Speeds: JML - 495, JKR - 341
5. JML one goes first and uses EFFLUX. Team one Jedi get 15% TM. Team two resist TM down due to first turn tenacity up.
6. JML two goes second and uses EFFLUX. Team two Jedi get 15% TM. Team jedi (other than JML) resist the TM reduction due to tenacity up.
7. Here's the surprise.... JKR 2 takes the next turn. I would have thought that JML 1's efflux would have filled or near filled JKR 1's TM prior to JKR 2. (even with the new 100% turn order changes).
My question is, "What is the formula to determine what speed JKR 1 would need to be in order to move before JKR 2?"
What are the variables here to calculate based on different JML/JKR speeds?
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Replies
85% speed is 458
So anyone less than that will not be pushed to 100% TM
JML of 496 speed
85% speed is 421
So anyone less than that will not be pushed to 100% tm
So neither JKR is at 85% TM when the push happens so neither will be at 100%
The faster JKR (JKR 2) will hit 100% first and take turn
So not a suprise
This is a very simplified example, but basically as long as JML2 gets to 100% before JKR1, its LIKELY his TM boost puts JKR2 'above' 100% TM before JKR1 gets there.
At least that is my understanding.
Also this is probably a better, more accurate explanation.
Note: this is not in any way their actual in battle speed it is just the speed they appear to move at based on the TM push. Actual speeds are used for any thing that looks at speed
Effective speed = speed / (1 - tm push)
In this instance
JKR 1 324 / 0.85 = 381
JKR 2 341 / 0.85 = 401
Thanks for the reply.
OK. I understand what you are saying, but is there a way to calculate what speed JKR 1 needs to be to move first?
Also, after JML1 pushes JKR1, does he not overtake JKR2 briefly and gain some additional increment of TM prior to the JML2 turn? or am I wrong in thinking that the 81 speed distance between JML 1 & 2 taking turns amounts to a significant additional amount of TM gain for JKR1?
JKR1 just needs to be faster than JKR2
Both are getting the same TM push
In the end they are both filling 85% of thier TM bar who gets the 15% push first doesn't matter unless it pushes one to 100%
Ok makes sense. I'm trying to overcomplicate I think. Thanks again.
Right. Unless you can get the JKR to be 85% of the GML's speed, the faster one will go first.
When 579 JML 1 goes, JKR1 is at 364/579 = 62.9%, JML2 at 535/579 = 92.4%, and JKR2 = 381/579=65.8%.
Team 1 gets 15%...JML 1 is at 15% and JKR1 is at 77.9%.
Now JML 2 goes, completing the other 7.6% tm, so JML1 is at 579/535*0.076+0.15 = 23.2%, JKR1 = 364/535*0.076+0.779 = 83%, JKR2 is 381/535*0.076+0.658 = 71.2%. Everyone gains tm, JML2 goes to 15%, JKR2 goes to 86.2%. So you can see that JKR2 still has more tm owing to the faster speed.
Edit: I saw that you said JKR is lead. So the tm from leadership is wrong. But the point still stands.
https://gaming-fans.com/2017/03/13/swgoh-look-speed-turn-meter-gain-turn-order-manipulation/